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TheBlueprintof Water

Chapter 7 · Corrosion · Ten playable problems

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5a

Ch 7 · P1The reactant you cannot fire

PROBLEM 61 · CORROSION THE FOUR COMPONENTS

Anode, cathode, electrolyte, metal path. In an open cooling tower, which cathodic reactant is effectively impossible to eliminate — and why?

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5b

Ch 7 · P2Breaking the ceasefire

PROBLEM 62 · CORROSION FILM SABOTEURS

Passivation is not immunity — it is a ceasefire. Match each of the four saboteurs to how it breaks it.

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5c

Ch 7 · P3The contractor's shortcut

PROBLEM 63 · CORROSION GALVANIC COUPLING

A new carbon steel header is threaded straight onto existing copper piping — no dielectric union. Click the metal that corrodes preferentially.

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5d

Ch 7 · P4Under the gasket

PROBLEM 64 · CORROSION CREVICE ATTACK

A gasket creates a crevice on a carbon steel flange in oxygenated water. Assign where the anode and cathode develop — then see why it accelerates.

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5e

Ch 7 · P5Weigh the coupon

PROBLEM 65 · CORROSION MPY FROM WEIGHT LOSS

A carbon steel coupon spends 90 days in the tower: 12.4500 g in, 12.1500 g out. Work the MPY, dial it, and classify the water.

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5f

Ch 7 · P6The ratio that would not move

PROBLEM 66 · CORROSION LARSON-SKOLD AT 6 CYCLES

Makeup: Cl⁻ 40, SO₄²⁻ 25, M-alkalinity 50. Cycle the tower up and watch the Larson-Skold ratio — then say what that reveals about bulk indices.

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5g

Ch 7 · P7Aim the counterattack

PROBLEM 67 · CORROSION WHICH LEG DOES EACH WEAPON HIT

Every treatment attacks one leg of the cell. Pick a weapon, then click the leg it is aimed at.

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5h

Ch 7 · P8The bolt and the header

PROBLEM 68 · CORROSION CURRENT DENSITY

Same two metals, opposite geometry. Click the configuration that destroys its steel fastest.

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5i

Ch 7 · P9Multiply, not add

PROBLEM 69 · CORROSION FOUR CONDITIONS AT ONCE

Elevated chloride, intermittent low-pH excursions, biofilm deposits, 6 MPY coupon loss — all at once. Why do these multiply risk instead of merely adding it?

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5j

Ch 7 · P10Ohm's law of a pit

PROBLEM 70 · CORROSION WHY A BREACH ACCELERATES

The passive film is breached. Current = Voltage ÷ Resistance — assign what happens to each term, and watch the current answer.

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